Create a recursive function evens(list_1) that takes a list and returns the number of even integers in it. Recall that you can check to see if n is even with n%2 == 0. For example,

>>> print(evens([5, 2, 9, 8, 9, 2, 6, 0, 9, 1]))
5
>>> print(evens([2, 4, 6, 8]))
4
>>> print(evens([1, 3, 5, 9]))
0
>>> print evens([])
0

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def evenslist1 if lenlist1 0 return 0 ... View the full answer