Question: cryptoghraphy 2 Q2: Fill the empty spaces regarding RSA encryption and dycryption: Given the public key (n,e)=kpub and the private key d=kpr we write y=ekpub(x)xemod..x=dkpr(y)ydmod.
Q2: Fill the empty spaces regarding RSA encryption and dycryption: Given the public key (n,e)=kpub and the private key d=kpr we write y=ekpub(x)xemod..x=dkpr(y)ydmod. where x,yZn We call ekpub() the encryption and dkpr() the decryption operation
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