Question: CT 1 0 3 a: ( CH ) N . B: CH = - 9 8 . 6 4 kcal / mol CO 2

CT10
"3a:
(CH)
N.B: CH =-98.64 kcal/mol CO2=-94.1 kcal/mol H2O(g)=-57.80 kcal/mol
3b:
(CH4)
N.B: CH4=-74.87 kcal/mol CO2=-94.1 kcal/mol H2O(g)=-57.80 kcal/mol
3c:
"" CO2(J/kg)
: CH 13/16/
3D:
"

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