Current Attempt in Progress

A $0\mathrm{.}58-$ kg particle is located at the position $r_1=(1\mathrm{.}1i+1\mathrm{.}7j+1\mathrm{.}1k)m$ and has the velocity $v_1=(5\mathrm{.}1i+6\mathrm{.}0j+3\mathrm{.}6k)\frac{m}{s}$ at time $t=0.$ If the

particle is acted upon by a single force which has the moment $M_O=([3\mathrm{.}4+1\mathrm{.}6t]i+[3\mathrm{.}4-0\mathrm{.}67t^2]j+5\mathrm{.}8k)N*m$ about the origin O of the

coordinate system in use, determine the angular momentum about $O$ of the particle when $t=6\mathrm{.}7s.$

Answer:

i

i

$j+C$

i

k$)kg*\frac{m^2}{s}$

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