Current Attempt in Progress

$($a$)$ How many grams of $KN{O}_3$ are needed to make $390mL$ of a solution that is to contain $4\mathrm{.}2m\frac{g}{m}L$ of potassium ion?

$gKN{O}_3$

$($b$)$ What is the molarity of the solution?

M

Incorrect. Did you convert grams to moles and then divide by the volume $($in L$)$ to calculate $M_1?$

To what volume must a solution of $92\mathrm{.}2g{H}_{2}S{O}_4$ in $517\mathrm{.}3mL$ of solution be diluted to give a $0\mathrm{.}11M$ solution?

Volume $=$

Current Attempt in Progress

How would you prepare $1000.mL$ of a $6\mathrm{.}00MHN{O}_3$ solution if only $3\mathrm{.}00M$ and $12\mathrm{.}0M$ solutions of the acid are available for mixing?

Mix together

$\frac{?}{\text{b}\text{a}\text{r}}(mL)3\mathrm{.}00MHN{O}_3$ and

$mL$ of $12\mathrm{.}0MHN{O}_3$ to get $1000.mL$ of $6\mathrm{.}00MHN{O}_3.$

eTextbook and Media

Current Attempt in Progress

When $80\mathrm{.}5mL$ of $0\mathrm{.}642$MBa$(N{O}_3{)}_2$ are mixed with $44\mathrm{.}5mL$ of $0\mathrm{.}743$MKOH, a precipitate of $Ba(OH{)}_2$ forms. How many grams of $Ba(OH{)}_2$ do you expect?

gBa$(OH{)}_2$

eTextbook and Media

Current Attempt in Progress

How many L of a $0\mathrm{.}25\%(\frac{v}{v})$ oil of wintergreen solution can you prepare if you have only $3\mathrm{.}52mL$ of oil of wintergreen on hand?

i

L

eTextbook and Media

For the equation below:

$Mg(s)+2HCl(aq)longrightarrowMgC{l}_2(aq)+H_2(g)$

$($a$)$ How many moles of hydrogen will be liberated from $139\mathrm{.}0mL$ of $4\mathrm{.}48MHCl$ reacting with an excess of magnesium?

$1mol{H}_2$

$($b$)$ How many liters of hydrogen gas $(H_2)$ measured at $30C$ and $716$ torr will be obtained?

$L{H}_2$