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The internal shear force $V$ at a certain section of an aluminum beam is $8\mathrm{.}3kN.$ If the beam has the cross section shown $($assume $a=34$

$mm,b_f=69mm,t_w=t_f=6mm,d=60mm),$ determine:

$($a$)$ the shear stress ${}_H$ at point $H,$ which is located $34mm$ above the bottom surface of the tee shape.

$($b$)$ the maximum horizontal shear stress ${}_{\text{m}\text{a}\text{x}}$ in the tee shape.

Answers:

$($a$){}_H=$

MPa.

$($b$){}_{\text{m}\text{a}\text{x}}=$

MPa.