Current Attempt in Progress Your answer is partially correct. Use the t-distribution to find a confidence interval for a difference in means - M given the relevant sample results. Give the best estimate for - M, the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. A 95% confidence interval for - using the sample results X1 = 74.4, s = 9.1, n = 30 and x2 = 62.0, s = 6.9, n : = 20 Enter the exact answer for the best estimate and round your answers for the margin of error and the confidence interval to two decimal places. Best estimate 12.4 Margin of error = i 5.53 Confidence interval: i 6.87 to 17.93