D$9\mathrm{.}1.$ Within a certain region, $lon={10}^{-11}\frac{F}{m}$ and $={10}^{-5}\frac{H}{m}.$ If $B_x=2{10}^{-4}cos{10}^{5}tsin{10}^{-3}yT$ : $($a$)$ use grad$H=lon\frac{\text{d}\text{e}\text{l}\text{E}}{\text{d}\text{e}\text{l}\text{t}}$ to find $E$; $($b$)$ find the total magnetic flux passing through the surface ${?}^4{?}^{5}t=1sE-20000sin{10}^{5}tcos{10}^{-3}y{a}_z\frac{V}{m}0\mathrm{.}318mWb$;$L{L}_{-3\mathrm{.}19V}o{\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}$vec$(E)*d=,=>t=1s1$vec$(E)=-20000sin(0\mathrm{.}1)(cos{10}^{-3})vec(a{)}_8.z=0=>{\displaystyle \underset{0}{\overset{4}{}}}{E}_z$vec$(a{)}_z*dyvec(ay)=0z=2.=>{\displaystyle \underset{4}{\overset{}{}}}{E}_z^{\text{'}}$vec$(a)-$dyvec$(a)y=0=-3\mathrm{.}196$

Please solve $($c$)$ only I dont know what is problem in my solution. Can you check it$?$ And have a correct answer Thank you