Question: (d) Consider the ODE du In (1 - sin2 u) dt 1 - e-2u (3) (i) Show that u = 0 is a fixed point

(d) Consider the ODE du In (1 - sin2 u) dt1 - e-2u (3) (i) Show that u = 0 is a

(d) Consider the ODE du In (1 - sin2 u) dt 1 - e-2u (3) (i) Show that u = 0 is a fixed point of the ODE. Hint 1: sina ~ a - + as 120 + ... for la|

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