Question: D E S k ( x ) = y = > D E S ? b a r ( k ) ( x ) ?

DESk(x)=y=>DES?bar(k)(x)?b=ar(y)
for every key k and input x, where ?bar(z) denotes the bitwise complement of z. This is
called the complementarity property of DES. Does this represent a serious vulnera-
bility in the use of triple-DES as a pseudorandom permutation? Explain.
D E S k ( x ) = y = > D E S ? b a r ( k ) ( x ) ?

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