Question: (d) The statement is true, but the proof is incorrect because the two given permutations, 0' and T actually commute. (e) The statement is true,
(d) The statement is true, but the proof is incorrect because the two given permutations, 0' and T actually commute. (e) The statement is true, but we do not know whether the set A actually contains elements 1, 2, 3, hence the oroof is incorrect. Reading Question 3.3.3. Consider the following statement, along with this "proof": . The "statement": If a set A has at least three elements, then the symmetric group SA is not abelian. . Its "proof": Let o E Sn be the permutation defined by o(1) = 2, (2) = 3, o(3) = 1, and o(x) x for x 2 1, 2, 3. Also, let T E S, be the permutation defined by 7(1) = 1, T(2) = 3, T(3) = 2, and r(x) = x for x # 1, 2, 3. Because or * To, the group SA is not abelian. Select the true claim(s). (a) The statement is true, but to prove that the group is not abelian, we must show that no two elements in the group commute. This proof is incomplete, thus incorrect. (b) The statement is false. (c) The statement is true, and the proof is correct
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