Data communication ..

Please solve Quickly please please i will give you upvote

just final answer without explantion ..

In an asenkron transmission a character size is 5 bits. When 2100 characters are transmitted, if total amount of data transmitted is 17,85 Kbit, which answer is correct? O a. Stop Bit - 1 Parity = Odd" Total Overhead = 7,50 Kbit O b. Stop Bit = 2 Parity - "No Total Overhead = 6,00 Kbit O c. Stop Bit = 15 Parity = "Even Total Overhead = 7,35 Kbit O d. Stop Bit = 1,5 Parity = "Even Total Overhead = 6,30 Kbit O e. Stop Bit - 2 Party - "Even" Total Overhead - 8,80 Kbit