Question: . data input: . asciiz Input: . text . globl main main: # Prompt user for input li $v 0 , 4 la $a

.data
input: .asciiz "Input: "
.text
.globl main
main:
# Prompt user for input
li $v0,4
la $a0, input
syscall
# Get user input
li $v0,5
syscall
move $a0, $v0
# Call Myfun(N)
jal Myfun
# Print the result
li $v0,1
syscall
# Exit
li $v0,10
syscall
# Function to recursively calculate Myfun(N)
Myfun:
# Save the return address and the argument ($a0) which contains N
addi $sp, $sp,-8 # Allocate stack space for 2 items
sw $ra,4($sp) # Save return address
sw $a0,0($sp) # Save argument N
# Base case: if N <3, return 0
slti $t0, $a0,3 # Check if N <3
bne $t0, $zero, base_case # if N <3, branch to end of function
# Recursive case: Myfun(N-2)+2N
# Calculate N-2 and call Myfun recursively
addi $a0, $a0,-2
jal Myfun
move $v0, $v0
# After returning from recursive call, retrieve N and calculate 2N
lw $t1,0($sp) # Load original N
add $t2, $t1, $t1 # $t1=2* N
# Add 2N to the result of the recursive call
add $v0, $v0, $t2 # $v0= $v0+ $t2
base_case:
li $v0,0
j end_myfun
end_myfun:
# Retrieve the original return address and restore the stack
lw $ra,4($sp) # Load the return address
addi $sp, $sp,8 # Deallocate stack space
# Return to caller
jr $ra # Jump back to the return address
When I input any number less than 3 it returns the input value, whenever I input 3 it outputs 1 instead of 0, when I input 4 it outputs 2 instead of 8

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