Question: Data of activity is as follows: (Reference for data : https://youtu.be/GlUZGUQKmKQ ) Toss (hr) Radioactive nuclei 0 240 1 117 2 64 3 34 4
Data of activity is as follows:
(Reference for data : https://youtu.be/GlUZGUQKmKQ )
| Toss (hr) | Radioactive nuclei |
| 0 | 240 |
| 1 | 117 |
| 2 | 64 |
| 3 | 34 |
| 4 | 13 |
| 5 | 6 |
| 6 | 4 |
| 7 | 0 |
1. Estimation of time of first 4 half life
Estimation of time up to 1st half life:
In 1st toss or 1hr the number of nuclei changed from 240 t0 117 ....for half life it must be around 120 nuclei
so estimated value of 1st half life = (120/123)hr= 0.975hr (approx.)
Estimation of time up to 2nd half life:
In 2nd toss or 2hr the number of nuclei changed from 117 t0 64 ....for half life it must be around 60 nuclei
so estimated value of 2nd half life = 1hr+(60/64)=1.938 hr (approx.)
Estimation of time up to 3rd half life:
In 3rd toss or 3hr the number of nuclei changed from 64 to 34 ....for half life it must be around 30 nuclei
so estimated value of 2nd half life = 2hr +(30/34)hr= 2.882hr (approx.)
Estimation of time up to 4th half life:
In 3rd toss or 3hr the number of nuclei changed from 34 to 13 ....for half life it must be around 15 nuclei
so estimated value of 2nd half life = 3hr +(15/17)hr= 3.882hr (approx.)
What is the reasoning behind the process to get these estimated values? Why do you do the following, (120/123)hr= 0.975hr (approx.) to get the estimated value of the 1st half-life, for example?
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
