Data on the angular position of a rotary sensor is taken over time, and the data is fit to a quadratic in LoggerPro. The results of the quadratic fit are given Auto Fit for: Latest | Angle Angle = A*1*2+Bt+C 20- here. What is the best-fit value of the angular A: 55.89 +/- 0.06169 B: -73,19 +/- 0.1269 acceleration of the rotary sensor? C: 23.96 +/- 0.06336 Correlation: 1.000 Angle (rad) RMSE: 0.008322 ra (A) 55.89 + 0.06 rad/s2 10- B ) - 73.19 + 0.13 rad / s C) 23.96 + 0.06 rad/s2 D) 111.78 + 0.12 rad/s2 06 10O 10 Time (s) 2. A cart of mass 0.700 + 0.005 kg travels at a speed of 2.50 + 0.01 m/s, as determined by a triple-beam balance and a motion sensor. The cart has a kinetic energy of 1/2 (.700 kg) (2.50 m/s)2 = 2.1875 J. Using the max-min method, what is the uncertainty in this value? " haxz ( 1 . 705 00 ) 2 . 51 ) = 1 . 76 955 (A) 0. 015 J B ) 0.020 J Mile (0. 69BR ) ( 2. 49 ) = 1:73 055 C ) 0.025 J D) 0.033 J Uncertainty = ( 1. 76 955 - 1. 73 055 ) / 2 = 0.0195 3. A rigid rod rotates around its own center, located at point C. Which point has the largest linear speed? A Point A B ) Point B C) Point C D) Point D 4. Consider the small portion of a car tire that is momentarily in contact with the ground as the car moves forward at a constant speed. At this moment, this portion of the car tire has acceleration: A) Forward B) Upward C) Downward D) Of zero magnitude 5. A 15-cm radius record rotates at a constant 33 1/3 rpm (revolutions per minute) as it plays. What is the centripetal acceleration of a point at the outer edge of the record? A) 0.52 m/s2 B) 1.8 m/ $2 ( 15 / 33 3 - 9 18 C) 81 m/s D) 17000 m/s2 Page 4 of 10