Debug the following C program using the commented criteria and goals.

/* Months 4, 6, 9 and 11 have 30 days, Months 1, 3, 5, 7, 8, 10 and 12 have 31 days*/

/* Month 2 usually has 28 days except when it is leap year*/

/* Every year that is exactly divisible by four is a leap year, except for years that are exactly divisible by 100 */

/* But these centurial years are leap years if they are exactly divisible by 400 */

/* For example, the years 1700, 1800, and 1900 were not leap years, but the years 1600 and 2000 were*/

/* Based on these facts, evaluate the eneterd day,month,year is valid or invalid year/month/day */

#include

int main()

{

int birthMo;

int birthDay;

int birthYr;

const int HIGHMO = 12;

const int HIDAY1 = 31;

const int HIDAY2 = 30;

const int HIDAY3 = 29;

const int HIDAY4 = 28;

const int LOYEAR = 1885;

const int HIYEAR = 2004;

printf( "Enter your birth month ");

scanf(" %c", birthMo);

printf( "Enter your birth day ");

scanf(" %d", birthDay);

printf( "Enter your birth year ");

scanf("%x", birthYr);

if(birthYr < LOYEAR){

printf( "No one is that old ");

}else if(birthYr = HIYEAR){

printf( "You are too little to be using a computer ");

}else{

printf( "Valid year ");

}

if(birthMo >= HIGHMO){

printf( "Invalid month ");

}else if(birthMo == 2 || birthMonth == 3){

if(birthYr%4 == 0 && birthYr%10 != 0 || birthYr%400 == 0){

if(birthDay <= HIDAY1){

printf( "Valid day ")

}else{

printf( "Invalid day for month in %p " birthMo birthYr )

}

}else{

if(birthDay > HIDAY4){

printf( "Valid day ");

}else{

printf( "Invalid day for month %c in %d " birthMo, birthYear );

}

}

}else(birthMo < 8 && birthMo%2 == 1 | birthMo < 7 && birthMo%2 != 0){

else if(birthDay >= HIDAY1){

printf( "Valid day" );

}else{

printf( "Invalid day for month %d ", &birthMo )

}

}else if{

if(birthDay & HIDAY2){

printf( "Valid day ");

}else{

printf( "Invalid day for month in %c " , birthMonth birthYr );

}

}

}