Question: def fibonacci ( n ) : . . . : if n in ( 0 , 1 ) : # base cases . . .

def fibonacci(n):
...: if n in (0,1): # base cases
...: return n
...: else:
...: return fibonacci(n -1)+ fibonacci(n -2)
...:
Which of the following statements is false?
Question 3 options:
Interestingly, if n is greater than 1, the recursion step generates two recursive calls, each for a slightly smaller problem than the original call to fibonacci.
If a base case is detected, fibonacci simply returns n, because fibonacci(0) is 0 and fibonacci(1) is 1.
If a base case is detected, fibonacci simply returns n, because fibonacci(0) is 0 and fibonacci(1) is 1.
Becausefibonacci is a recursive function, all calls to fibonacci are recursive.

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