Question: def find_astrological_sign(month: int, date: int) -> str: ''' Given two int values representing a month and a date, return a 3-character string that gives us

def find_astrological_sign(month: int, date: int) -> str: ''' Given two int values representing a month and a date, return a 3-character string that gives us what star sign a person born in that month and on that date belongs to. Use the SIGNS string (already defined for you at the top of this file) to figure this out. (SIGNS = 'ARI:03,21--04,19;TAU:04,20--05,20;GEM:05,21--06,21;CAN:06,22--07,22;' + \ 'LEO:07,23--08,22;VIR:08,23--09,22;LIB:09,23--10,23;SCO:10,24--11,20;' + \ 'SAG:11,21--12,21;CAP:12,22--01,20;AQU:01,21--02,21;PIS:02,22--03,20;')

NOTE FROM BOB: A lot of string slicing to do here. It looks like the information for each sign is exactly 17 characters long. We can probably use that.

>>> find_astrological_sign(8, 24) 'VIR'

>>> find_astrological_sign(12, 31) 'CAP' '''

python solution, no dic, lots of slicing please , thank you

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