Question: def foo ( n ) : if n = = 1 : return 1 if n % 2 = = 0 : return n +

def foo(n):
if n ==1: return 1
if n%2==0: return n + foo(n//2)
return foo(3*n+1)
Can you implement the function foo from the previous question using dynamic programming and bottom-up iteration?
If yes, give an implementation; if no, explain what difficulties do you encounter.

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