Define the following methods: calcVol$()$ has two double parameters as a cone's radius and height. The method returns the cone's volume as a double, and

uses the calcBaseArea$()$ method to calculate the cone's base area. The volume is calculated by:

Volume $=$ base area $*$ height $*\frac{1\mathrm{.}0}{3\mathrm{.}0}$

$$ Click here for example

Ex: If the input is $2\mathrm{.}03\mathrm{.}0,$ then the output is:

Cone radius: $2\mathrm{.}0$

Cone height: $3\mathrm{.}0$

Base area: $12\mathrm{.}6$

Volume: $12\mathrm{.}6$

Note: Use Math.PI for $.$ public class ConeCalculations $\{$public static void main$($String$[]$ args$)\{$ double coneRadius; coneRadius $=$ scan.nextDouble$()$; System.out.println$("$Cone radius: $"+$ coneRadius$)$; System.out.printf$("$Base area: $\%\mathrm{.}1$f

$",$ calcBaseArea$($coneRadius$))$; System.out.printf$("\%\mathrm{.}1$f

$",$ calcVol$($coneRadius$,$ coneHeight$))$; Failed to compile

ConeCalculations.java:$15$: error: $\text{'}$;$\text{'}$ expected

return baseArea height $(1\mathrm{.}0/3\mathrm{.}0)$;

$1$ error

calcBaseArea$()$ has one double parameter as a cone's radius. The method returns the area of the cone's base as a double. The area of the base is calculated by:

calcVol$()$ has two double parameters as a cone's radius and height. The method returns the cone's volume as a double, and uses the calcBaseArea$()$ method to calculate the cone's base area. The volume is calculated by:

Click here for example

Ex: If the input is $2\mathrm{.}03\mathrm{.}0,$ then the output is:

Cone radius: $2\mathrm{.}0$

Cone height: $3\mathrm{.}0$

Base area: $12\mathrm{.}6$

Volume: $12\mathrm{.}6$

Note: Use Math.PI for

$.$