Question: delta =(PA)/(LE)+alpha LDelta T, , is this equation consistent? (circle one) Yes I No a. delta = displacement [in];L= length [mm];E=modulus of elasticity [Pa];A=area[m^(2)] ;
\\\\delta =(PA)/(LE)+\\\\alpha L\\\\Delta T,, is this equation consistent? (circle one) Yes I No\ a.
\\\\delta =displacement
[in];L=length
[mm];E=modulusof elasticity
[Pa];A=area[m^(2)];\
\\\\Delta T=Temperature change
[\\\\deg R];P=pressure
[mmHg];\\\\alpha =coefficient of thermal expansion
(1)/(K) 
3) =LEPA+LT, is this equation consistent? (circle one) Yes I No a. = displacement [in]; L= length [mm]; E= modulus of elasticity [Pa];A=area[m2]; T= Temperature change [R];P= pressure [mmHg];= coefficient of thermal expansion [1/K]
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