Describe the behavior $off(x)$ when $x$ approaches from the left $of$ the vertical asymptote

$off(x)=\frac{1}{x+1}$

$asx$ approaches the vertical asymptote $atx=-1,f(x)$ goes $to-$

$asx$ approaches the vertical asymptote $atx=1,f(x)$ goes $to+$

$asx$ approaches the vertical asymptote $atx=0,f(x)$ goes $to+$

$asx$ approaches the vertical asymptote $atx=-2,f(x)$ goes $to-$