Question: Description Implement a class in Java named InfixToPostfixConverter containing the following meth- ods. In an infix expression an operator is written in between the two

 Description Implement a class in Java named InfixToPostfixConverter containing the followingmeth- ods. In an infix expression an operator is written in between

Description Implement a class in Java named InfixToPostfixConverter containing the following meth- ods. In an infix expression an operator is written in between the two operands. In contrast, in an postfix expression an operator is written after the operands. Consider the following expression for explanation. If the infix expression is 2 3 6 1, then its postfix version is 2 3 6 * The program must not ask for any kind of input from the user. No file reading is required too. You must assume the followin g regarding the input infix exp They will contain only integers as operands. The only operator they can contain are these four: *, /, +, They will not contain any parenthesis or any kind of brace. A number and a operator are separated by a whitespace. Example: 2844 33 * 49 - 9 /67 OPERATOR PRIORITY RULES , * and / have same priority + and-have same priority Priority of *,/ is greater than that of +, - F To represent priority, one can assign integers to the operators. Note that the methods are defined as public static. This means without creating an object, one should be able to use the methods. Just like the widely used Integer.parseInt(String s) method. In the following two methods, we need stacks for implementing the algorithms. You must define the stack class inside the InfixToPostfixConverter class 1. public static String infix2Postfix(String infixExpression); This method returns the postfix version of the infix expression passed to this method. But make sure that the operators and numbers are separated by a whitespace. Description Implement a class in Java named InfixToPostfixConverter containing the following meth- ods. In an infix expression an operator is written in between the two operands. In contrast, in an postfix expression an operator is written after the operands. Consider the following expression for explanation. If the infix expression is 2 3 6 1, then its postfix version is 2 3 6 * The program must not ask for any kind of input from the user. No file reading is required too. You must assume the followin g regarding the input infix exp They will contain only integers as operands. The only operator they can contain are these four: *, /, +, They will not contain any parenthesis or any kind of brace. A number and a operator are separated by a whitespace. Example: 2844 33 * 49 - 9 /67 OPERATOR PRIORITY RULES , * and / have same priority + and-have same priority Priority of *,/ is greater than that of +, - F To represent priority, one can assign integers to the operators. Note that the methods are defined as public static. This means without creating an object, one should be able to use the methods. Just like the widely used Integer.parseInt(String s) method. In the following two methods, we need stacks for implementing the algorithms. You must define the stack class inside the InfixToPostfixConverter class 1. public static String infix2Postfix(String infixExpression); This method returns the postfix version of the infix expression passed to this method. But make sure that the operators and numbers are separated by a whitespace

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