Question: Design a magnitude comparator that takes two 2-bit binary numbers, A2A1 and B2B1, and determine their status based on below condition, If A2A1 >=
Design a magnitude comparator that takes two 2-bit binary numbers, A2A1 and B2B1, and determine their status based on below condition, If A2A1 >= B2B1 then GREATER_OR_EQUAL = 1 If A2A1 B2B1 then LESS = 1 This comparator circuit contains of FOUR inputs (A2A1 and B2B1) and TWO outputs (GREATER_OR_EQUAL and LESS). (i) Derive the truth table for the above problem. (ii) Minimized the expression into simplified SOP form using K-map. (iii) Draw the combinational logic diagram based on the simplified Boolean expression as in (ii) (iv) Verify your truth table with the constructed logic circuit (Construct your circuit in circuitverse and screenshot your results)
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
