Determine $g^{\text{'}}(x)$ if $g(x)=ln(\frac{x^{2}5x8}{x^{3}5x8})$

Select the correct answer below:

$g^{\text{'}}(x)=\frac{2x-5}{x^{2}5x8}-\frac{3x^2-5}{x^{3}5x8}$

$g^{\text{'}}(x)=\frac{x^{2}5x8}{2x5}-\frac{x^{3}5x8}{3x^{2}5}$

$g^{\text{'}}(x)=\frac{2x5}{x^{2}5x8}-\frac{3x^{2}5}{x^{2}5x8}$

$g^{\text{'}}(x)=\frac{2x5}{x^{2}5x8}\frac{3x^{2}5}{x^{2}5x8}$