Determine $r^{\text{'}}(x)$ for $r(x)=\frac{x^3}{(x-1)e^{\text{'}}}$ using logarithmic differentiation.

Select the correct answer below:

$r^{\text{'}}(x)=(\frac{-x^{2}5x-5}{x-1})$

$r^{\text{'}}(x)=\frac{x^4}{(x-1)e^x}(\frac{-x^{2}5x-5}{x-1})$

$r^{\text{'}}(x)=\frac{x^2}{(x-1)e^2}(\frac{4x5}{x-1})$