Question: Determine the data flow graph for the below source code. Then, state the minimal set of test cases that achieves all-c-uses/some-p-uses, all-p-uses/some-c-uses, and all-du-paths coverage

 Determine the data flow graph for the below source code. Then,

Determine the data flow graph for the below source code. Then, state the minimal set of test cases that achieves all-c-uses/some-p-uses, all-p-uses/some-c-uses, and all-du-paths coverage for variables ti and tv. Clearly state which du-paths are needed for all-c-uses/some-p-uses coverage, which ones for all-p-uses/some-c-uses coverage, and which ones for all-du-paths coverage. Explain which test cases in your set are needed for all-c-uses/some-p-uses coverage, which ones for all-p-uses/some-c-uses coverage, and which ones for all-du-paths coverage. For each test case, state the required test input. public static double ReturnAverage(int valuel], int AS, int MIN, int MAX) int i, ti, tv, sum; double av; i = 0; t = 0; tv = 0; sum = 0; while (ti AS && value [i] !--999) { ti++ if (value[i]MIN&&value[i]- MAX) tv+t; sum = sum + value[1]; av-(double) sum/tv; else av-(double) -999; return (av) Determine the data flow graph for the below source code. Then, state the minimal set of test cases that achieves all-c-uses/some-p-uses, all-p-uses/some-c-uses, and all-du-paths coverage for variables ti and tv. Clearly state which du-paths are needed for all-c-uses/some-p-uses coverage, which ones for all-p-uses/some-c-uses coverage, and which ones for all-du-paths coverage. Explain which test cases in your set are needed for all-c-uses/some-p-uses coverage, which ones for all-p-uses/some-c-uses coverage, and which ones for all-du-paths coverage. For each test case, state the required test input. public static double ReturnAverage(int valuel], int AS, int MIN, int MAX) int i, ti, tv, sum; double av; i = 0; t = 0; tv = 0; sum = 0; while (ti AS && value [i] !--999) { ti++ if (value[i]MIN&&value[i]- MAX) tv+t; sum = sum + value[1]; av-(double) sum/tv; else av-(double) -999; return (av)

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