Determine the derivative $of$ the function: $,y=ln(secx+tanx)$

$\frac{dy}{dx}=secx$

$\frac{dy}{dx}=tanx$

$\frac{dy}{dx}=se{c}^{2}x$

$\frac{dy}{dx}=cosx+cotx$

$\frac{dy}{dx}=1+cotx$