Determine the forces in members $\backslash ($ D E $\backslash )$ and $\backslash ($ D L $\backslash ).$ The forces are positive if in tension, negative if in compression.

Part $1$

If we cut through $\backslash ($ D E$,$ E L $\backslash ),$ and $\backslash ($ L K $\backslash ),$ we can isolate the section to the right of the cut. This section does not have any external reactions, so there is no need to solve for the reactions. The free$-$body diagram of this section is shown. All members of the truss are assumed to be in tension.

Solve for the force in $\backslash ($ D E $\backslash ).$ You can do this with one carefully chosen equation.

Answer: $\backslash ($ D E$=\backslash )$