Determine the head loss $(h_L)$ across a pipe of length $6900$ ft $,$ if it's diameter is

$19$ inches and the material is uncoated steel $($i$.$e$.,C=100).$ The discharge along

the pipe section is $600\mathrm{.}5$ gpm $.$ Calculate the value to the nearest $0\mathrm{.}1$ ft $.$

Useful equations:

$Q=0\mathrm{.}285C_h{D}^{2\mathrm{.}63}{S}^{0\mathrm{.}54}$

$h_L=L[\frac{Q}{0\mathrm{.}285C_h{D}^{2\mathrm{.}63}}{]}^{1\mathrm{.}852}$

$D=[\frac{Q}{0\mathrm{.}285C_h{S}^{0\mathrm{.}54}}{]}^{0\mathrm{.}38}$

$Q$ in $ga\frac{l}{m}in$

$D$ in inches

$h_L$ in feet

$S$ in $f\frac{t}{f}t$

Answer: