Determine the$$ interval$($s$)$ on which the function

f left parenthesis x right parenthesis equals e Superscript StartRoot x minus $1$ EndRootf$($x$)=$ex$1$

is$$ continuous, then evaluate the limits

ModifyingBelow lim With x right arrow $2$ f left parenthesis x right parenthesislimx$2$f$($x$)$

and

ModifyingBelow lim With x right arrow $1$ Superscript plus f left parenthesis x right parenthesislimx$1+$f$($x$).$