Determine the local maximum and minimum values of f(x) = X3 4X2 +12 using the second derivative test when it applies. Local maximum value is 12 at X = 0. O 68 8 Local minimum value is at X = . 2? 3 Local minimum value is 8 at X = 0. Local maximum value is 8 at X = 3. Local maximum value is 8 at X = 0. Local minimum value is 8 at X = . 3 Local minimum value is 12 at X = 0. O 88 8 Local maximum value is atX = . 27 3