Determine the maximum load P that the column can carry if the maximum stress not to exceed 120 MPa. Solve this problem by using the Secant formula, start with Po=1000 kPa, P-2000 kPa. Manually show all detailed steps and iterations clearly by using tables. The aluminum W420 x 2020 (wide flange) colum is subject to an eccentric axial load P as shown above. The maximum compressive stress in the column is given by where * = = [1 + 1 sec ( / ) ] max 1+ P/A: average stress A = 25800 mm : cross-sectional area of the column e = 85 mm : eccentricity of the load c = 170 mm : half-depth of the column r = 142 mm : radius of gyration of the cross-section L = 7100 mm: length of the column E = 71-10 Pa elasticity modulus ;