Question: did i do this right? In(:) - - Ex [t+] Homework Question 01 In the following reaction, R= 8.314 x 10-3 kJ/molok 4 NH3 +
In(:) - - Ex [t+] Homework Question 01 In the following reaction, R= 8.314 x 10-3 kJ/molok 4 NH3 + 702 4NO2 + 6H2O The activation energy, Eq, is 126 kJ/mol and the rate constant at 30 C is 9.8 x 10-3 min-1. What is the rate constant at 35 C? E = 126 kJ/mol min Inl 9,8x100 8.314 x103 308.15 303,75 o Labels Ti = 30C + 273,15 K T, = 303.15 K In(ka) - In(9.8*10*%) = (-15155.15997)(-0,000053524) k=? T2 = 35C +273.15K T = 308.15K - 126 Ky = 9,8x10-3 In(ka) -4.625372893 = 0.811164782 In (k) - 5.436537075 (k = 2,3 x 10 min 2
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
