Question: differential equation (1 point) A spring with a 2-kg mass and a damping constant 7 can be held stretched 1.5 meters beyond its natural length

differential equation

differential equation (1 point) A spring with a 2-kg mass and a

(1 point) A spring with a 2-kg mass and a damping constant 7 can be held stretched 1.5 meters beyond its natural length by a force of 3 newtons. Suppose the spring is stretched 3 meters beyond its natural length and then released with zero velocity. In the notation of the text, what is the value c2 - 4mk? m2kg2/sec Find the position of the mass, in meters, after t seconds. Your answer should be a function of the variable t of the form cle + cell where a = (the larger of the two) B = (the smaller of the two) " =

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