Question: DIfferential Equation Obtain the particular solution satisfying the initial condition indicated. 1. (3x2 - 2xy + 3y' )dx = 4xydy; when x = 1, y
DIfferential Equation

Obtain the particular solution satisfying the initial condition indicated. 1. (3x2 - 2xy + 3y' )dx = 4xydy; when x = 1, y = 2 2. ydx = (x+vy - x- dy; when x = 0, y =1 3. xydx - (x' + 3y dy =0; when x = 0, y =1 4.v dx + x(x+v)dv =0; when x = 1,v =1
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