Question: Differentiate. f ( x ) = 1 - 8 x 2 + ( 1 - 4 x ) 2 f ' ( x ) =

Differentiate.
f(x)=1-8x2+(1-4x)2
f'(x)=-41-8x2-8(1-4x)
f'(x)=41-8x2+8(1-4x)
f'(x)=-81-8x2-4(1-4x)
f'(x)=121-8x2+2(1-4x)
Differentiate. f ( x ) = 1 - 8 x 2 + ( 1 - 4 x )

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