Question: Differentiate. J(V)= (V^3 - 2V)(V^-4 + V^-2) I used the product rule. => J'(V) = (V^3) - 2V) d/dx(V^-4 + V^-2) + (V^-4 + V^-2)

Differentiate. J(V)= (V^3 - 2V)(V^-4 + V^-2) I used the product rule.

=> J'(V) = (V^3) - 2V) d/dx(V^-4 + V^-2) + (V^-4 + V^-2) d/dx( V^3 -2V)

= (V^3 - 2V)(-4V^-5 - 2V^-3) + (V^-4 + V^-2)(3V^2 - 2)

= -4V^-2 - 2V +8V^-4 + 2V^-2 + 3V^-2 - 2V^-4 + 3V - 2V^-2

= 6V^-4 - V^-2 - 2V

The answer is suppose to be 6V^-4 + V^-2 + 1. Please show me where I went wrong

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