Differentiate the function.

$y=\frac{6x^2-1}{2x^{3}7}$

Which of the following shows how to find the derivative of $f(x)?$

A$.y^{\text{'}}=\frac{(2x^{3}7)(\frac{d}{dx}(6x^2-1))-(6x^2-1)(\frac{d}{dx}(2x^{3}7))}{(2x^{3}7)}$

B$.y^{\text{'}}=\frac{(6x^2-1)(\frac{d}{dx}(6x^2-1))-(2x^{3}7)(\frac{d}{dx}(2x^{3}7))}{(2x^{3}7{)}^2}$

c$.y^{\text{'}}=\frac{(2x^{3}7)(\frac{d}{dx}(6x^2-1))-(6x^2-1)(\frac{d}{dx}(2x^{3}7))}{(2x^{3}7{)}^2}$

D$.y^{\text{'}}=(2x^{3}7)(\frac{d}{dx}(6x^2-1))-(6x^2-1)(\frac{d}{dx}(2x^{3}7))$