Disregard all current working, please use formulas and working to solve for all parts

1) f (x) =-2x+1 (6 points) a) find the slope of the secant line b) find the slope of the tangent line c) find the equation of the between x = 3 and x = 8 at x = 3 f = (shti ) tangent line at x = 3 f ( 3 ) = - 2 ( 3 ) + 1 = - 5 + ( xoth ) - f ( x o ) 4- yo = m ( x- no ) ( 3 , - 5 ) f ( 8 ) = - 2 (8 ) +1 = - 15 h f ( 3 ) : - 2 ( 3 ) +1 ( 8 , - 5 ) 42- 4 1 = =15 - (25) = -10 =- 2 f ( 3th ) - f (3 ) f ( s ) - - 6 + 8 - 3 f = - 2 3 y +6 = -2 ( 3+1 ) -2 f ( 3h ) = - 2x+1 f - ( 6 h +1 ) - f (s ) 2) f ( x) = x- -x-2 (6 points) f = ( 2hti ) - f ( 1 ) a) find the slope of the secant line b) find the slope of the tangent line find the equation of the between x = -1 and x = 4 at x = 2 f ( utzhitzhth? )-f ( tangent line at x = 2 f ( - 1 ) = - 12 ( - 1( 2 ) f(xoth ) -f ( x ) 4-40 = m (x-xo ) ( - 1,2 ) = - 1+1 +2 h f ( 2 th th + 1 2) - 0 = 3 (2 - 2 ) = 2 ( 43 (0 ) f ( 4 ) = 4 2 - 4 - 2 f ( 2th) - f(2 ) f= ( 2ththth ? ) f ( 2 ) 1 = 22 2- 2 2 = 4- 2-2 = 16- 4-2 f ( z H = * 2 x - 2 ) - 10 R. ( zth ) f ( zth ) 92-41 10 - 2 - yo = 2 ( 2 - 2 ) X 2-XI 4 - ( - 1 ) F ( 4+zh+ zh+2 2 ) -f( 2 ) 3 ) f ( x) = x+ 3 (6 points) 2 x- 1