Do booth algorithm $7$x$5$ in the way it is done in the picture $7$ is multiplicant $(8$bits$)$and $5$ is product $(16$ bits$)$

$\backslash$table$[[$Iteration$,$Step,Multd,Product$],[0,0$ initial,$00001010,00000000000010000],[1,1$ shift,$00001010,00000000000001000],[2,2$ shift,$00001010,00000000000000100],[3,3$ shift,$00001010,00000000000000010],[4,4$ A $=$ A $-$ M$,00001010,11110110000000010],[4,5$ shift,$00001010,11111011000000001],[5,6A=A+M,00001010,0000010100000000$