DO NOT answer part B, only answer this part of the question PART A, as part B is not posted here. I only want part A, and I want all of the steps written out. If you can't do that DO NOT ANSWER thank you :)

3.15 A theorem by Tolman states that the activation energy for a reaction is the difference between the average energy of those molecules that react and the average energy of all the molecules: E. - . Show for a general reaction of cross section ol) that the rate constant is = 3/2 2 1/2 Er k(T) = 271 20 (741)" ()" 406, Jexp(*) de. 2) TKT KT