Question: do second one The numbers 1, 2, ..., 2n are divided into two groups of n numbers. Prove that the pairwise sums of numbers in

do second one The numbers 1, 2, ..., 2n aredo second one The numbers 1, 2, ..., 2n are

do second one

The numbers 1, 2, ..., 2n are divided into two groups of n numbers. Prove that the pairwise sums of numbers in each group (the sum of each number with itself included) have the same remainders upon division by 2n. (Note: each pair of distinct numbers should be added twice, and each remainder must occur the same number of times in the two groups.) The positive integers m, n, m, n are written on a blackboard. A generalized Euclidean algorithm is applied to this quadruple as fol- lows: if the numbers x, y, u, v appear on the board and x > y, then 3 y, y, u + v, v are written instead; otherwise x,y - 3,u,v + u are written instead. The algorithm stops when the numbers in the first pair become equal (they will equal the greatest common divisor of m and n). Prove that the arithmetic mean of the numbers in the second pair at that moment equals the least common multiple of m and n. The numbers 1, 2, ..., 2n are divided into two groups of n numbers. Prove that the pairwise sums of numbers in each group (the sum of each number with itself included) have the same remainders upon division by 2n. (Note: each pair of distinct numbers should be added twice, and each remainder must occur the same number of times in the two groups.) The positive integers m, n, m, n are written on a blackboard. A generalized Euclidean algorithm is applied to this quadruple as fol- lows: if the numbers x, y, u, v appear on the board and x > y, then 3 y, y, u + v, v are written instead; otherwise x,y - 3,u,v + u are written instead. The algorithm stops when the numbers in the first pair become equal (they will equal the greatest common divisor of m and n). Prove that the arithmetic mean of the numbers in the second pair at that moment equals the least common multiple of m and n

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