Do the question w the same method on the right

Two drivers, Alison and Kevin, are participating in a race. Beginning from a Anonymous answered this standing start, they each proceed with a constant acceleration. Alison covers 13,875 answers the last - - F 13 of the distance in 11 seconds, whereas Kevin covers the last- For Alison, assume the first 1/4 of the distance is L, of the distance in 13 seconds. Who wins and by how much time? theacceleration is a, the time is t1, then L = at12/2, at1 = V(2L/a) the first 1/4 and the second 1/4 of the distance is 2L, the time ist2, then 2L = atz2/2,.tz = V(4L/a) = V2t1 the first 1/4, the second 1/4 and the third 1/4 ofthe Kevin wins the race by 3.46 seconds. distance is 3L, the time is to, then 3L =at32/2, at3 = (Type an integer or decimal rounded to the nearest tenth as needed.) V(6L/a)= V3 t1 the whole distance is 4L, the time is t4, then 4L =at42/2, :t4 = V(8L/a)= V4t1 the question gives t4 - t3 = (V4 - V3)t1= 3s :t1 = 3/(V4 - V3) = 3(V4 + V3) s the total time = t4 = V4 ty =3V4(V4 + V3) =612+v3) s = 22.4 s Similarly for Kevin we may get the total time = V3 *4/(V3 - V2) = 4V3(V3 + V2) = 4*13 + V6) = 21.8 s answer: Kevin wins by 0.6 s