Do you know how i can solve the problem using python code?

Given is the price of a stock for n days. Determine the maximum possible profit if you could buy and sell the stock at most twice. You are allowed to hold at most one stock at a time. Additionally, if you buy the stock for the second time, there must be at least one day in between when you didn't have the stock.

The time complexity of the algorithm should be O$($n$).$

Implement the function, which returns the desired result.

python code

def find$($t$)$:

# TODO

if $\_\_$name$\_\_=="\_\_$main$\_\_"$:

print$($find$([1,5,2,1,5]))$ # $8$

print$($find$([1,5,1,5]))$ # $4$

print$($find$([1,2,3,4,5]))$ # $4$

print$($find$([5,4,3,2,1]))$ # $0$

print$($find$([4,2,5,8,7,6,1,2,5,1]))$ # $10$

Explanation: When the prices are $[1,5,2,1,5],$ a profit of $8$ is obtained by repeating buying and selling twice at the prices of $1$ and $5.$ When the prices are $[1,5,1,5],$ this is not possible because there must be at least one day between selling and buying. Therefore, you can only get a profit of $4$ by buying and selling the stock once.