Do you think the normal density function accurately describes the distance Michael hits with a pitching wedge? why?

a. no because the bars in the histogram are sometimes higher than the normal curve and sometimes lower.

b. yes, because the distance Michael hits the ball is a random variable so it is normally distributed.

c. no because the normal distribution is continuous but the distance Michael hits the ball is a discrete variable.

d. yes because the histogram shape resembles a normal curve and the area of each bar is roughly equal to the area under the normal curve for the same region.

 

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Michael went to the driving range with his range finder and hit 75 golf balls with his pitching wedge and measured the distance each ball traveled (in yards). The accompanying table shows his data. Complete parts a and b below. Click the icon to view the table of drive distances. a. Use technology to construct a relative frequency histogram. Comment on the shape of the distribution. Draw a normal density function on the relative frequency histogram. Choose the correct relative frequency histogram below. i Golf Drive Distances O B. O A. Q Q 0.32- 100 98 102 0.16- 101 101 101 103 98 98 102 103 01 93 96 99 102 105 2 101 Distance (yards) 97 102 100 99 102 Q 97 102 100 100 102 100 100 25- 12.5- 104 100 100 101 97 100 100 99 93 96 99 102 105 96 98 97 Distance (yards) Comment on the shape of the distribution. O A. The shape of the distribution is approximately normal. O B. The shape of the distribution is approximately uniform. O C. The shape of the distribution seems to have no pattern. Draw a normal density function on the relative frequency histogram. Choose the correct answer below. O A. Q 25- 12.5- 93 96 99 102 105 Distance (yards) 93 96 99 Click to select your answer. O C. O. C. Relative Fr Relative Freq. Relative Freq. Relative Freq. 07 0.32- 0.16- 0+ 102 105 Q O D. OB. O D. Relative Freq. Relative Freq. Relative Freq. Relative Freq. 0.32 0.16- 03 93 96 99 102 105 Distance (yards) 93 96 99 102 105 Distance (yards) 25- 12.5- 93 0.32- 0.16- 25- 12.5-3 07 93 96 99 102 105 Distance (yards) 99 102 105 96 Q G Q Q Q Q E 101 101 98 101 99 102 99 100 99 100 98 100 103 101 104 101 102 99 100 102 101 99 100 100 99 96 99 100 100 101 102 101 Done Print 99 100 99 101 99 97 97 100 O X Michael went to the driving range with his range finder and hit 75 golf balls with his pitching wedge and measured the distance each ball traveled (in yards). The accompanying table shows his data. Complete parts a and b below. Click the icon to view the table of drive distances. a. Use technology to construct a relative frequency histogram. Comment on the shape of the distribution. Draw a normal density function on the relative frequency histogram. Choose the correct relative frequency histogram below. i Golf Drive Distances O B. O A. Q Q 0.32- 100 98 102 0.16- 101 101 101 103 98 98 102 103 01 93 96 99 102 105 2 101 Distance (yards) 97 102 100 99 102 Q 97 102 100 100 102 100 100 25- 12.5- 104 100 100 101 97 100 100 99 93 96 99 102 105 96 98 97 Distance (yards) Comment on the shape of the distribution. O A. The shape of the distribution is approximately normal. O B. The shape of the distribution is approximately uniform. O C. The shape of the distribution seems to have no pattern. Draw a normal density function on the relative frequency histogram. Choose the correct answer below. O A. Q 25- 12.5- 93 96 99 102 105 Distance (yards) 93 96 99 Click to select your answer. O C. O. C. Relative Fr Relative Freq. Relative Freq. Relative Freq. 07 0.32- 0.16- 0+ 102 105 Q O D. OB. O D. Relative Freq. Relative Freq. Relative Freq. Relative Freq. 0.32 0.16- 03 93 96 99 102 105 Distance (yards) 93 96 99 102 105 Distance (yards) 25- 12.5- 93 0.32- 0.16- 25- 12.5-3 07 93 96 99 102 105 Distance (yards) 99 102 105 96 Q G Q Q Q Q E 101 101 98 101 99 102 99 100 99 100 98 100 103 101 104 101 102 99 100 102 101 99 100 100 99 96 99 100 100 101 102 101 Done Print 99 100 99 101 99 97 97 100 O X

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Ans d yes because the histogram shape resembles a normal curve and the area of each bar is roughly e... View the full answer