Question: $ ( document ) . ready ( ) What is the reason why all jQuery method / function calls are placed inside this 'ready' function?

$(document).ready()
What is the reason why all jQuery method/function calls are placed inside this 'ready' function?
Group of answer choices
To make sure that the web page is fully loaded into the browser window before any jQuery scripts begin to run.
To make sure that the browser is ready to run jQuery scripts.
To make sure that the browser has javaScript enabled.
To make sure that the server has responded to the web page request.

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