Question: does this look right? I did the a=4, b=2, d=2, a = b^d == O(n^d logb(n)) = O(n^2log2(n)) What is the order of growth for

does this look right? I did the a=4, b=2, d=2, a = b^d == O(n^d logb(n)) = O(n^2log2(n))

What is the order of growth for solution of the following recurrence: T(n) = 4T(n/2) + n?, n 1, T(1) = 1. O O(nlogn) O Oin logn) O No answer text provided. O o(n ])

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