Question: Doesnt need the Reynolds part, only need the direct evaluation part by vector calculus with spherical coordinates x-xol=t Exercise 3. Let H(x) be a smooth

Doesnt need the Reynolds part, only need the direct evaluation part

Doesnt need the Reynolds part, only need the direct evaluation part by vector calculus with spherical coordinates

\x-xol=t Exercise 3. Let H(x) be a smooth scalar function. Show by two different methods, namely, Reynold's Transport Theorem and direct evaluation that d H(x) dx = H(x)ds, dt x-xol

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