Question: Done 6 myopenmath.com AA (3 Chapter 9.2 - 9.3 Homework Score: 8.45/11 7/11 answered Progress saved Done (3) wlc. 0 Question 1 v a 0.5/1

 Done 6 myopenmath.com AA (3 Chapter 9.2 - 9.3 Homework Score:8.45/11 7/11 answered Progress saved Done (3) wlc. 0 Question 1 va 0.5/1 pt '0 3 8 98 G) Details Give a 90%confidence interval, for #1 #2 given the following information. 111 : 20,5:1 : 2, 81 : 0.5 Hz : 55, 5:2 : 1.84,.32 : 0.86 :I: Use Technology Rounded to 2 decimal places. HintQuestion Help: Video 8 Message instructor Submit Question Done 6 myopenmath.com AA0 Chapter 9.1 Homework Score: 6.16/9 6/9 answered Progress saved Done (3)
wlc. 0 Question 2 v 80/1 pt '0 3 8 99 G)Details A random sample of m = 224 people who live ina city were selected and 104 identified as a "dog person." Arandom sample of 712 = 100 people who live in a ruralarea were selected and 56 identified as a "dog person." Find the90% confidence interval for the difference in the proportion of people thatlive in a city who identify as a "dog person" and theproportion of people that live in a rural area who identify as

Done 6 myopenmath.com AA (3 Chapter 9.2 - 9.3 Homework Score: 8.45/11 7/11 answered Progress saved Done (3) wlc. 0 Question 1 v a 0.5/1 pt '0 3 8 98 G) Details Give a 90% confidence interval, for #1 #2 given the following information. 111 : 20, 5:1 : 2, 81 : 0.5 Hz : 55, 5:2 : 1.84, .32 : 0.86 :I: Use Technology Rounded to 2 decimal places. Hint Question Help: Video 8 Message instructor Submit Question Done 6 myopenmath.com AA 0 Chapter 9.1 Homework Score: 6.16/9 6/9 answered Progress saved Done (3) wlc. 0 Question 2 v 80/1 pt '0 3 8 99 G) Details A random sample of m = 224 people who live in a city were selected and 104 identified as a "dog person." A random sample of 712 = 100 people who live in a rural area were selected and 56 identified as a "dog person." Find the 90% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. 80.91/1 pt '0 3 8 98 G) Details A new beta-blocker medication is being tested to treat high blood pressure. Subjects with high blood pressure volunteered to take part in the experiment. 180 subjects were randomly assigned to receive a placebo and 290 received the medicine. High blood pressure disappeared in 80 of the controls and in 145 of the treatment group. Test the claim that the new beta- blocker medicine is effective at a significance level of a = 0.10. What are the correct hypotheses? H02 Select an answer 0 ? v Select an answer 0 ? 3 Select an answer 3 0 H12 Select an answer Based on the hypotheses, find the following: Test Statistic = p-value = The test statistic is: Select an answer 0 The correct decision is to Select an answer 0 The correct summary would be: Select an answer Q the claim that the new beta-blocker medicine is effective at a significance level of a = 0.10. 9.2+09.3 myopenmath.com . Question 5 UD H1 :PN > PD H1 :PN # PD O O O Ho : MN 2 ND HO : UN = MD HO : PN 2 PD H1: UN l3 0/1 pt '0 3 8 98 G) Details You are testing the claim that the mean GPA of night students is different than the mean GPA of day students. You sample 55 night students, and the sample mean GPA is 2.13 with a standard deviation of 0.96 You sample 20 day students, and the sample mean GPA is 2.23 with a standard deviation of 0.31 Calculate the test statistic, rounded to 2 decimal places Question Help: 8 Message instructor Submit Question 51-11954} Progress saved Done cE'p wlc. i myopenmath.com . Question 9 v E 0.65/1 pt 0 3 3 98 (D Details You wish to test the following claim (Ha) at a significance level of a : 0.002. For the context of this problem, ,ud : p2 m where the first data set represents a pre-test and the second data set represents a post-test. Horpd=0 Hazpd > 0 You believe the population of difference scores is normally distributed, but you do not know the standard deviation. You obtain pre-test and post-test samples for n : 273 subjects. The average difference (post - pre) is d : 6.2 with a standard deviation of the differences of 3d : 35.4. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the P-value for this test? For this calculation, use the conservative under-estimate for the degrees of freedom as mentioned in the textbook. (Report answer accurate to four decimal places.) P-value = The P-value is... less than (or equal to) or greater than 04 This P-value leads to a decision to... reject the null accept the null fail to reject the null E myopenmath.com Chapter 9.1 Homework Score: 6.16/9 5/9 answered Progress saved Done (3) wlc. 0 Question 8 v 80/1 pt '0 3 8 99 G) Details A new beta-blocker medication is being tested to treat high blood pressure. Subjects with high blood pressure volunteered to take part in the experiment. 180 subjects were randomly assigned to receive a placebo and 210 received the medicine. High blood pressure disappeared in 100 of the controls and in 114 of the treatment group. Test the claim that the new beta- blocker medicine is effective at a significance level of a = 0.01. What are the correct hypotheses? 0 H0: Select an answer C ? G Select an answer 0 Ha: Select an answer 0 ? G Select an answer Based on the hypotheses, find the following: Test Statistic = (Round your answer to four decimal places.) p-value = (Round your answer to four decimal places. ) The correct decision is to Select an answer 0 The correct summary would be: Select an answer 0 the claim that the new beta-blocker medicine is effective at a significance level of oz = 0.01. Question Help: 8 Message instructor B myopenmath.com . Question 9 v E 0.25/1 pt 0 2-3 8 99 G) Details Score on last try: 0.25 of 1 pts. See Details for more. 8 Get a similar question You can retry this question below A National Cancer Institute study published in 1991 examined the incidence of cancer in dogs. Of 827 dogs whose owners used the weed killer 2-4-D on their lawns or gardens, 473 were found to have cancer. Only 19 of the 130 dogs that had not been exposed to this herbicide had cancer. Construct a 95% confidence interval for the difference in pets' cancer risk. Name the Interval: O 2 Sample T Interval O 2 Proportion Z Interval O 1 Proportion Z Interval O T Interval 05 Create and Interpret the confidence interval: Interval : ( , ) Interpretation : Question Help: 8 Message instructor Submit

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